---
id: 587d8253367417b2b2512c6b
title: Remove from a Set
challengeType: 1
videoUrl: ''
localeTitle: 从集合中删除
---
## Description
在本练习中，我们将为我们的集创建一个删除函数。该函数应命名为this.remove 。此函数应接受一个值并检查它是否存在于集合中。如果是，请从集合中删除该值，然后返回true。否则，返回false。
## Instructions
## Tests
```yml
tests:
- text: 您的Set类应该有一个remove方法。
testString: 'assert((function(){var test = new Set(); return (typeof test.remove === "function")}()), "Your Set class should have a remove method.");'
- text: 您的remove方法应该只删除集合中存在的项目。
testString: 'assert.deepEqual((function(){var test = new Set(); test.add("a");test.add("b");test.remove("c"); return test.values(); })(), ["a", "b"], "Your remove method should only remove items that are present in the set.");'
- text: 您的remove方法应从集合中删除给定的项目。
testString: 'assert((function(){var test = new Set(); test.add("a");test.add("b");test.remove("a"); var vals = test.values(); return (vals[0] === "b" && vals.length === 1)}()), "Your remove method should remove the given item from the set.");'
```
## Challenge Seed
```js
function Set() {
// the var collection will hold the set
var collection = [];
// this method will check for the presence of an element and return true or false
this.has = function(element) {
return (collection.indexOf(element) !== -1);
};
// this method will return all the values in the set
this.values = function() {
return collection;
};
// this method will add an element to the set
this.add = function(element) {
if(!this.has(element)){
collection.push(element);
return true;
}
return false;
};
// change code below this line
// change code above this line
}
```
## Solution
```js
// solution required
```