---
id: 587d8253367417b2b2512c6c
title: Perform a Union on Two Sets
challengeType: 1
videoUrl: ''
localeTitle: 在两个集上执行联合
---
## Description
在本练习中，我们将对两组数据执行联合。我们将在我们的Set数据结构上创建一个名为union 。此方法应将另一个Set作为参数，并返回两个集合的union集，不包括任何重复值。例如，如果setA = ['a','b','c']和setB = ['a','b','d','e'] ，则setA和setB的并集为： setA.union(setB) = ['a', 'b', 'c', 'd', 'e'] 。
## Instructions
## Tests
```yml
tests:
- text: 你的Set类应该有一个union方法。
testString: 'assert((function(){var test = new Set(); return (typeof test.union === "function")})(), "Your Set class should have a union method.");'
- text: 收回了适当的收藏
testString: 'assert((function(){var setA = new Set(); var setB = new Set(); setA.add("a"); setA.add("b"); setA.add("c"); setB.add("c"); setB.add("d"); var unionSetAB = setA.union(setB); var final = unionSetAB.values(); return (final.indexOf("a") !== -1 && final.indexOf("b") !== -1 && final.indexOf("c") !== -1 && final.indexOf("d") !== -1 && final.length === 4)})(), "The proper collection was returned");'
```
## Challenge Seed
```js
function Set() {
// the var collection will hold the set
var collection = [];
// this method will check for the presence of an element and return true or false
this.has = function(element) {
return (collection.indexOf(element) !== -1);
};
// this method will return all the values in the set
this.values = function() {
return collection;
};
// this method will add an element to the set
this.add = function(element) {
if(!this.has(element)){
collection.push(element);
return true;
}
return false;
};
// this method will remove an element from a set
this.remove = function(element) {
if(this.has(element)){
var index = collection.indexOf(element);
collection.splice(index,1);
return true;
}
return false;
};
// this method will return the size of the set
this.size = function() {
return collection.length;
};
// change code below this line
// change code above this line
}
```
## Solution
```js
// solution required
```